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Add an article on interfacing with automatic differentiation.
Doing this also necessitated some re-organization of the derivatives article into chapters and some minor edits. Change-Id: Ic08e83af138817173caa80a52a9e72707cd57512
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.. default-domain:: cpp
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.. cpp:namespace:: ceres
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.. _chapter-automatic_derivatives:
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=====================
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Automatic Derivatives
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=====================
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We will now consider automatic differentiation. It is a technique that
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can compute exact derivatives, fast, while requiring about the same
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effort from the user as is needed to use numerical differentiation.
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Don't believe me? Well here goes. The following code fragment
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implements an automatically differentiated ``CostFunction`` for `Rat43
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<http://www.itl.nist.gov/div898/strd/nls/data/ratkowsky3.shtml>`_.
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.. code-block:: c++
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struct Rat43CostFunctor {
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Rat43CostFunctor(const double x, const double y) : x_(x), y_(y) {}
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template <typename T>
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bool operator()(const T* parameters, T* residuals) const {
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const T b1 = parameters[0];
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const T b2 = parameters[1];
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const T b3 = parameters[2];
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const T b4 = parameters[3];
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residuals[0] = b1 * pow(1.0 + exp(b2 - b3 * x_), -1.0 / b4) - y_;
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return true;
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}
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private:
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const double x_;
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const double y_;
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};
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CostFunction* cost_function =
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new AutoDiffCostFunction<Rat43CostFunctor, 1, 4>(
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new Rat43CostFunctor(x, y));
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Notice that compared to numeric differentiation, the only difference
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when defining the functor for use with automatic differentiation is
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the signature of the ``operator()``.
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In the case of numeric differentition it was
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.. code-block:: c++
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bool operator()(const double* parameters, double* residuals) const;
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and for automatic differentiation it is a templated function of the
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form
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.. code-block:: c++
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template <typename T> bool operator()(const T* parameters, T* residuals) const;
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So what does this small change buy us? The following table compares
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the time it takes to evaluate the residual and the Jacobian for
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`Rat43` using various methods.
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========================== =========
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CostFunction Time (ns)
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========================== =========
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Rat43Analytic 255
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Rat43AnalyticOptimized 92
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Rat43NumericDiffForward 262
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Rat43NumericDiffCentral 517
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Rat43NumericDiffRidders 3760
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Rat43AutomaticDiff 129
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========================== =========
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We can get exact derivatives using automatic differentiation
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(``Rat43AutomaticDiff``) with about the same effort that is required
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to write the code for numeric differentiation but only :math:`40\%`
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slower than hand optimized analytical derivatives.
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So how does it work? For this we will have to learn about **Dual
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Numbers** and **Jets** .
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Dual Numbers & Jets
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===================
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.. NOTE::
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Reading this and the next section on implementing Jets is not
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necessary to use automatic differentiation in Ceres Solver. But
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knowing the basics of how Jets work is useful when debugging and
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reasoning about the performance of automatic differentiation.
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Dual numbers are an extension of the real numbers analogous to complex
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numbers: whereas complex numbers augment the reals by introducing an
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imaginary unit :math:`\iota` such that :math:`\iota^2 = -1`, dual
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numbers introduce an *infinitesimal* unit :math:`\epsilon` such that
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:math:`\epsilon^2 = 0` . A dual number :math:`a + v\epsilon` has two
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components, the *real* component :math:`a` and the *infinitesimal*
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component :math:`v`.
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Surprisingly, this simple change leads to a convenient method for
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computing exact derivatives without needing to manipulate complicated
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symbolic expressions.
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For example, consider the function
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.. math::
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f(x) = x^2 ,
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Then,
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.. math::
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\begin{align}
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f(10 + \epsilon) &= (10 + \epsilon)^2\\
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&= 100 + 20 \epsilon + \epsilon^2\\
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&= 100 + 20 \epsilon
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\end{align}
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Observe that the coefficient of :math:`\epsilon` is :math:`Df(10) =
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20`. Indeed this generalizes to functions which are not
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polynomial. Consider an arbitrary differentiable function
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:math:`f(x)`. Then we can evaluate :math:`f(x + \epsilon)` by
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considering the Taylor expansion of :math:`f` near :math:`x`, which
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gives us the infinite series
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.. math::
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\begin{align}
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f(x + \epsilon) &= f(x) + Df(x) \epsilon + D^2f(x)
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\frac{\epsilon^2}{2} + D^3f(x) \frac{\epsilon^3}{6} + \cdots\\
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f(x + \epsilon) &= f(x) + Df(x) \epsilon
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\end{align}
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Here we are using the fact that :math:`\epsilon^2 = 0`.
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A `Jet <https://en.wikipedia.org/wiki/Jet_(mathematics)>`_ is a
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:math:`n`-dimensional dual number, where we augment the real numbers
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with :math:`n` infinitesimal units :math:`\epsilon_i,\ i=1,...,n` with
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the property that :math:`\forall i, j\ :\epsilon_i\epsilon_j = 0`. Then
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a Jet consists of a *real* part :math:`a` and a :math:`n`-dimensional
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*infinitesimal* part :math:`\mathbf{v}`, i.e.,
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.. math::
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x = a + \sum_j v_{j} \epsilon_j
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The summation notation gets tedious, so we will also just write
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.. math::
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x = a + \mathbf{v}.
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where the :math:`\epsilon_i`'s are implict. Then, using the same
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Taylor series expansion used above, we can see that:
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.. math::
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f(a + \mathbf{v}) = f(a) + Df(a) \mathbf{v}.
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Similarly for a multivariate function
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:math:`f:\mathbb{R}^{n}\rightarrow \mathbb{R}^m`, evaluated on
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:math:`x_i = a_i + \mathbf{v}_i,\ \forall i = 1,...,n`:
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.. math::
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f(x_1,..., x_n) = f(a_1, ..., a_n) + \sum_i D_i f(a_1, ..., a_n) \mathbf{v}_i
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So if each :math:`\mathbf{v}_i = e_i` were the :math:`i^{\text{th}}`
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standard basis vector, then, the above expression would simplify to
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.. math::
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f(x_1,..., x_n) = f(a_1, ..., a_n) + \sum_i D_i f(a_1, ..., a_n) \epsilon_i
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and we can extract the coordinates of the Jacobian by inspecting the
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coefficients of :math:`\epsilon_i`.
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Implementing Jets
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-----------------
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In order for the above to work in practice, we will need the ability
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to evaluate an arbitrary function :math:`f` not just on real numbers
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but also on dual numbers, but one does not usually evaluate functions
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by evaluating their Taylor expansions,
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This is where C++ templates and operator overloading comes into
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play. The following code fragment has a simple implementation of a
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``Jet`` and some operators/functions that operate on them.
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.. code-block:: c++
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template<int N> struct Jet {
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double a;
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Eigen::Matrix<double, 1, N> v;
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};
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template<int N> Jet<N> operator+(const Jet<N>& f, const Jet<N>& g) {
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return Jet<N>(f.a + g.a, f.v + g.v);
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}
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template<int N> Jet<N> operator-(const Jet<N>& f, const Jet<N>& g) {
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return Jet<N>(f.a - g.a, f.v - g.v);
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}
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template<int N> Jet<N> operator*(const Jet<N>& f, const Jet<N>& g) {
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return Jet<N>(f.a * g.a, f.a * g.v + f.v * g.a);
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}
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template<int N> Jet<N> operator/(const Jet<N>& f, const Jet<N>& g) {
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return Jet<N>(f.a / g.a, f.v / g.a - f.a * g.v / (g.a * g.a));
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}
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template <int N> Jet<N> exp(const Jet<N>& f) {
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return Jet<T, N>(exp(f.a), exp(f.a) * f.v);
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}
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// This is a simple implementation for illustration purposes, the
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// actual implementation of pow requires careful handling of a number
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// of corner cases.
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template <int N> Jet<N> pow(const Jet<N>& f, const Jet<N>& g) {
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return Jet<N>(pow(f.a, g.a),
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g.a * pow(f.a, g.a - 1.0) * f.v +
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pow(f.a, g.a) * log(f.a); * g.v);
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}
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With these overloaded functions in hand, we can now call
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``Rat43CostFunctor`` with an array of Jets instead of doubles. Putting
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that together with appropriately initialized Jets allows us to compute
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the Jacobian as follows:
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.. code-block:: c++
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class Rat43Automatic : public ceres::SizedCostFunction<1,4> {
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public:
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Rat43Automatic(const Rat43CostFunctor* functor) : functor_(functor) {}
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virtual ~Rat43Automatic() {}
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virtual bool Evaluate(double const* const* parameters,
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double* residuals,
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double** jacobians) const {
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// Just evaluate the residuals if Jacobians are not required.
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if (!jacobians) return (*functor_)(parameters[0], residuals);
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// Initialize the Jets
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ceres::Jet<4> jets[4];
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for (int i = 0; i < 4; ++i) {
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jets[i].a = parameters[0][i];
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jets[i].v.setZero();
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jets[i].v[i] = 1.0;
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}
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ceres::Jet<4> result;
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(*functor_)(jets, &result);
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// Copy the values out of the Jet.
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residuals[0] = result.a;
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for (int i = 0; i < 4; ++i) {
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jacobians[0][i] = result.v[i];
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}
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return true;
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}
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private:
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std::unique_ptr<const Rat43CostFunctor> functor_;
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};
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Indeed, this is essentially how :class:`AutoDiffCostFunction` works.
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Pitfalls
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========
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Automatic differentiation frees the user from the burden of computing
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and reasoning about the symbolic expressions for the Jacobians, but
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this freedom comes at a cost. For example consider the following
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simple functor:
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.. code-block:: c++
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struct Functor {
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template <typename T> bool operator()(const T* x, T* residual) const {
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residual[0] = 1.0 - sqrt(x[0] * x[0] + x[1] * x[1]);
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return true;
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}
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};
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Looking at the code for the residual computation, one does not foresee
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any problems. However, if we look at the analytical expressions for
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the Jacobian:
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.. math::
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y &= 1 - \sqrt{x_0^2 + x_1^2}\\
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D_1y &= -\frac{x_0}{\sqrt{x_0^2 + x_1^2}},\
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D_2y = -\frac{x_1}{\sqrt{x_0^2 + x_1^2}}
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we find that it is an indeterminate form at :math:`x_0 = 0, x_1 =
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0`.
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There is no single solution to this problem. In some cases one needs
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to reason explicitly about the points where indeterminacy may occur
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and use alternate expressions using `L'Hopital's rule
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<https://en.wikipedia.org/wiki/L'H%C3%B4pital's_rule>`_ (see for
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example some of the conversion routines in `rotation.h
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<https://github.com/ceres-solver/ceres-solver/blob/master/include/ceres/rotation.h>`_. In
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other cases, one may need to regularize the expressions to eliminate
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these points.
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