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Diagon/test/Math_style=Latex/lim/output
T

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\lim_{a} b \\
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\lim_{x \to \infty} x = \infty \\
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\lim_{x \to ∞} \sqrt{x + \frac{1}{x}} = \infty \\
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\lim_{x \to ∞} \sqrt{x + \frac{1}{x}} = \frac{1}{2}